Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 32 - AC Circuits - Exercises and Problems - Page 924: 11


$C = 8.1\times 10^{-8}~F$

Work Step by Step

We can find the capacitance $C$: $I_C = V_C~\omega~C$ $C = \frac{I_C}{V_C~\omega}$ $C = \frac{I_C}{\sqrt{2}~V_{rms}~2\pi~f}$ $C = \frac{65\times 10^{-3}~A}{(\sqrt{2})~(6.0~V)~(2\pi) (15\times 10^3~Hz)}$ $C = 8.1\times 10^{-8}~F$
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