## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson

# Chapter 3 - Vectors and Coordinates Systems - Exercises and Problems - Page 78: 34

#### Answer

(a) $\theta = 33.6^{\circ}$ (b) $v_y = 1.7~m/s$

#### Work Step by Step

(a) $v_x = v~cos(\theta)$ $cos(\theta) = \frac{v_x}{v}$ $\theta = arccos(\frac{2.5~m/s}{3.0~m/s})$ $\theta = 33.6^{\circ}$ (b) $v_y = v~sin(\theta)$ $v_y = (3.0~m/s)~sin(33.6^{\circ})$ $v_y = 1.7~m/s$

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