Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 3 - Vectors and Coordinates Systems - Exercises and Problems: 25

Answer

$C = (-4.9~\hat{i}-1.9~\hat{j})~m$

Work Step by Step

$A+B+C = 0$ $C = -(A+B)$ $C_x = -(A_x+B_x)$ $C_x = -[4~m~cos(40^{\circ})+2~m~cos(20^{\circ})]$ $C_x= -4.9~m$ $C_y = -(A_y+B_y)$ $C_y = -[4~m~sin(40^{\circ})-2~m~sin(20^{\circ})]$ $C_y = -1.9~m$ $C = (-4.9~\hat{i}-1.9~\hat{j})~m$
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