Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 3 - Vectors and Coordinates Systems - Exercises and Problems: 32

Answer

The component of the cannonball's velocity that is parallel to the ground is 86.6 m/s

Work Step by Step

The horizontal component of the velocity is parallel to the ground. Therefore; $v_x = v~cos(\theta)$ $v_x = (100~m/s)~cos(30^{\circ})$ $v_x = 86.6~m/s$ The component of the cannonball's velocity that is parallel to the ground is 86.6 m/s.
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