Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 3 - Vectors and Coordinates Systems - Exercises and Problems: 27

Answer

The required vector is $(0.707~\hat{i}+0.707~\hat{j})$

Work Step by Step

The vector ($\hat{i}+\hat{j}$) points at a $45^{\circ}$ angle above the positive x-axis. The vectors which point in this direction have the form $(k\hat{i}+k\hat{j})$ for some positive constant $k$. Therefore, $\sqrt{k^2+k^2} = 1$ $\sqrt{2k^2} = 1$ $k = \frac{1}{\sqrt{2}}$ $k = 0.707$ This means that the required vector is $(0.707~\hat{i}+0.707~\hat{j})$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.