Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 26 - Potential and Field - Exercises and Problems - Page 738: 32


$E = 1200~N/C$

Work Step by Step

Let $V$ be the volume of the space. We can find the strength of the electric field $E$: $\frac{U}{V} = \frac{1}{2}\epsilon_0~E^2$ $E^2 = \frac{2U}{V\epsilon_0}$ $E = \sqrt{\frac{2U}{V\epsilon_0}}$ $E = \sqrt{\frac{(2)(50\times 10^{-12}~J)}{(0.020~m)^3(8.854\times 10^{-12}~F/m)}}$ $E = 1200~N/C$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.