Answer
$C = 3.0~\mu F$
Work Step by Step
We can find the equivalent capacitance $C$:
$\frac{1}{C} = \frac{1}{6.0\times 10^{-6}~F}+\frac{1}{10\times 10^{-6}~F}+\frac{1}{16\times 10^{-6}~F}$
$\frac{1}{C} = \frac{(10)(16)}{(10)(16)(6.0\times 10^{-6}~F)}+\frac{(6.0)(16)}{(6.0)(16)(10\times 10^{-6}~F)}+\frac{(6.0)(10)}{(6.0)(10)(16\times 10^{-6}~F)}$
$\frac{1}{C} = \frac{316}{(10)(16)(6.0\times 10^{-6}~F)}$
$C = \frac{(10)(16)(6.0\times 10^{-6}~F)}{316}$
$C = 3.0~\mu F$