Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 26 - Potential and Field - Exercises and Problems - Page 738: 18

Answer

$Q = 3.0~C$

Work Step by Step

We can find the charge $Q$: $W = Q~\Delta V$ $Q = \frac{W}{\Delta V}$ $Q = \frac{27~J}{9.0~ V}$ $Q = 3.0~C$
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