Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 26 - Potential and Field - Exercises and Problems - Page 738: 26


$C = 32~\mu F$

Work Step by Step

We can find the equivalent capacitance $C$: $C = (6.0\times 10^{-6}~F)+(10\times 10^{-6}~F)+(16\times 10^{-6}~F)$ $C = 32\times 10^{-6}~F$ $C = 32~\mu F$
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