#### Answer

After the force ends, the object's speed is 2.0 m/s in the original direction.

#### Work Step by Step

We can use the graph to find the impulse exerted on the object. The impulse is equal to the area under the force versus time graph.
$J = F~t$
$J = (2~N)(1.0~s)$
$J = 2.0~N~s$
We then use the impulse to find the final momentum $p_f$.
$p_f = p_0+J$
$p_f = m~v_0+J$
$p_f = (2.0~kg)(1.0~m/s)+2.0~N~s$
$p_f = 4.0~N~s$
We then find the velocity $v_f$ after the force ends;
$m~v_f = p_f$
$v_f = \frac{p_f}{m}$
$v_f = \frac{4.0~N~s}{2.0~kg}$
$v_f = 2.0~m/s$
After the force ends, the object's speed is 2.0 m/s in the original direction.