## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

We can use the information in the bar chart to find the initial momentum $p_0$. $p_0 + J = p_f$ $p_0 = p_f - J$ $p_0 = 2~kg~m/s - 6~kg~m/s$ $p_0 = -4~kg~m/s$ We then find the initial velocity $v_0$ of the particle; $m~v_0 = p_0$ $v_0 = \frac{p_0}{m}$ $v_0 = \frac{-4~kg~m/s}{0.050~kg}$ $v_0 = -80~m/s$ Before the impulse, the speed of the particle was 80 m/s in the negative direction.