## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson

# Chapter 9 - Impulse and Momentum - Exercises and Problems - Page 240: 7

#### Answer

The average collision force exerted on the object was 800 N in the negative direction.

#### Work Step by Step

We can use the information in the bar chart to find the impulse $J$. $p_0 + J = p_f$ $J = p_f - p_0$ $J = -2~kg~m/s-6~kg~m/s$ $J = -8~kg~m/s$ We then use the impulse to find the average force. $F~t = J$ $F = \frac{J}{t}$ $F = \frac{-8~kg~m/s}{10\times 10^{-3}~s}$ $F = -800~N$ The average collision force exerted on the object was 800 N in the negative direction.

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