## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson

# Chapter 9 - Impulse and Momentum - Exercises and Problems - Page 240: 12

#### Answer

The ball's rebound velocity is 6.0 m/s

#### Work Step by Step

We can use the graph to find the impulse exerted on the ball. The impulse is equal to the area under the force versus time graph. $J = ~F_x~t$ $J = (500~N)(8.0\times 10^{-3}~s)$ $J = 4.0~N~s$ We can use the impulse to find the final momentum $p_f$. $p_f = p_0+J$ $p_f = m~v_0+J$ $p_f = (0.25~kg)(-10~m/s)+4.0~N~s$ $p_f = 1.5~N~s$ We can use the final momentum to find the rebound velocity $v_{fx}$. $m~v_{fx} = p_f$ $v_{fx} = \frac{p_f}{m}$ $v_{fx} = \frac{1.5~N~s}{0.25~kg}$ $v_{fx} = 6.0~m/s$ The ball's rebound velocity is 6.0 m/s.

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