Answer
$25.6W$
Work Step by Step
We can find the required heat loss rate as follows:
$P=e\sigma \pi D(h+\frac{D}{4})(T^4-T_{\circ}^4)$
We plug in the known values to obtain:
$P=(0.95)(5.67\times 10^{-8})\pi(0.2)(0.2+\frac{0.2}{4})[(308)^4-(278)^4]$
This simplifies to:
$P=25.6W$
