Answer
(a) $91.25J$
(b) $140K$
Work Step by Step
(a) We can find the required heat as follows:
$Q=\frac{m}{M}C_p\Delta T$
We plug in the known values to obtain:
$Q=\frac{1}{32}(29.2)(100)$
$Q=91.25J$
(b) We can find the required temperature as follows:
$\Delta T_v=\frac{nC_p\Delta T_p}{nC_v}$
$\implies \Delta T_v=1.40(100)$
$\implies \Delta T=140K$