Answer
(a) $31.25J$
(b) $59.9K$
Work Step by Step
(a) We can determine the required heat as follows:
$Q=\frac{m}{M}C_v\Delta T$
We plug in the known values to obtain:
$Q=\frac{1}{40}(12.5)(100)$
$\implies Q=31.25J$
(b) The required temperature can be determined as follows:
$\Delta T_p=\frac{nC_v\Delta T_v}{nC_p}$
$\implies \Delta T_p=\frac{1}{\gamma}\Delta T_v$
We plug in the known values to obtain:
$\Delta T_p=\frac{1}{1.67}(100)$
$\implies \Delta T_p=59.9K$
