Answer
See the graph below.
Work Step by Step
The given figure shows that the temperature is constant while the pressure increases and the volume decreases.
So it is a compression-isothermal process.
$$\boxed{\Delta T = 0}$$
The work done is positive since $dV$ is negative because the volume of the gas decreases.
$$\boxed{W\gt 0}$$
And since the temperature is constant and the work is positive, the heat exchange must be negative.
$$E_{th}=Q\downarrow+W\uparrow$$
Thus,
$$\boxed{Q\lt 0}$$
See the bar-charts graph of this process below.
