#### Answer

$5.25\times 10^4~J$ of heat energy must be added to the block of aluminum.

#### Work Step by Step

We can find the mass of the block as:
$m = \rho~V$
$m = (2700~kg/m^3)(0.060~m)^3$
$m = 0.5832~kg$
The heat energy $Q$ required to raise the temperature of a substance is:
$Q = m~c~\Delta T$
We then find the heat energy required to raise the temperature of the aluminum block:
$Q = m~c~\Delta T$
$Q = (0.5832~kg)(900~J/kg~C^{\circ})(100~C^{\circ})$
$Q = 5.25\times 10^4~J$
$5.25\times 10^4~J$ of heat energy must be added to the block of aluminum.