Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 17 - Work, Heat, and the First Law of Thermodynamics - Exercises and Problems: 11

Answer

$5.25\times 10^4~J$ of heat energy must be added to the block of aluminum.

Work Step by Step

We can find the mass of the block as: $m = \rho~V$ $m = (2700~kg/m^3)(0.060~m)^3$ $m = 0.5832~kg$ The heat energy $Q$ required to raise the temperature of a substance is: $Q = m~c~\Delta T$ We then find the heat energy required to raise the temperature of the aluminum block: $Q = m~c~\Delta T$ $Q = (0.5832~kg)(900~J/kg~C^{\circ})(100~C^{\circ})$ $Q = 5.25\times 10^4~J$ $5.25\times 10^4~J$ of heat energy must be added to the block of aluminum.
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