Answer
(a) $238.08J$
(b) $330.05J$
Work Step by Step
(a) We can find the required work done at constant pressure as follows:
$W=-\frac{nRT_i}{V_i}(V_f-V_i)$
We plug in the known values to obtain:
$W=-\frac{(0.1)(8.31)(573)}{2000\times 10^{-6}}(1000\times 10^{-6}-2000\times 10^{-6})$
This simplifies to:
$W=238.08J$
(b) We know that
$W=-nRT\ln \frac{V_f}{V_i}$
We plug in the known values to obtain:
$W=-(0.1)(8.31)(573)\ln(\frac{1000\times 10^{-6}}{2000\times 10^{-6}})$
This simplifies to:
$W=330.05J$
