## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

We can calculate the work done as: $W = P\Delta V$ $W = P ~(V_f-V_i)$ $W = (2.00\times 10^5~Pa)(100\times 10^{-6}~m^3-300\times 10^{-6}~m^3)$ $W = -40~J$ The minus sign shows that 40 J of work is done on the gas.