# Chapter 15 - Fluids and Elasticity - Exercises and Problems: 32

(a) The force exerted on the flat end of each cylinder is $2.9\times 10^4~N$ (b) 30 football players would need to hang from the lower cylinder to pull the two cylinders apart.

#### Work Step by Step

(a) The pressure difference between the inside of the cylinders and the outside of the cylinders is $1~atm$. We can find the force exerted on the flat end of each cylinder. $F = \Delta P~A$ $F = \Delta P~\pi~r^2$ $F = (1.013\times 10^5~N/m^2)(\pi)(0.30~m)^2$ $F = 2.9\times 10^4~N$ The force exerted on the flat end of each cylinder is $2.9\times 10^4~N$ (b) We find the weight of one football player. $weight = (100~kg)(9.80~m/s^2) = 980~N$ We then find the number $n$ of football players. $n\times ~weight = 2.9\times 10^4~N$ $n = \frac{2.9\times 10^4~N}{weight}$ $n = \frac{2.9\times 10^4~N}{980~N}$ $n = 30~players$ 30 football players would need to hang from the lower cylinder to pull the two cylinders apart.

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