Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 15 - Fluids and Elasticity - Exercises and Problems - Page 436: 10


The force required to pull the cover off is 630 N

Work Step by Step

We can find the pressure difference between the pressure on the inside of the cover and the pressure on the outside of the cover. $\Delta P = P_0 - P_i$ $\Delta P = (1.01\times 10^5~Pa)-(2.0\times 10^4~Pa)$ $\Delta P = 8.01\times 10^4~Pa$ Then we find the force required to pull off the cover. $F = (\Delta P)~(Area~of~the~hole)$ $F = (8.01\times 10^4~N/m^2)(\pi)(0.05~m)^2$ $F = 630~N$ The force required to pull the cover off is 630 N.
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