## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

We can use Young's modulus to solve this question: $Y = \frac{F/A}{\Delta~L/L} = \frac{F~L}{A~\Delta L}$ For concrete, $Y = 30\times 10^9~N/m^2$ We then find the the distance $\Delta L$ that the column is compressed; $Y = \frac{F~L}{A~\Delta L}$ $\Delta L = \frac{F~L}{A~Y}$ $\Delta L = \frac{(200,000~kg)(9.80~m/s^2)(3.0~m)}{(\pi)(0.25~m)^2~(30\times 10^9~N/m^2)}$ $\Delta L = 0.0010~m = 1.0~mm$ The column is compressed by 1.0 mm