Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 11 - Work - Exercises and Problems - Page 303: 20

Answer

At $y=0$: $F_y = 0$ At $y=1~m$: $F_y = -12~N$ At $y=2~m$: $F_y = -48~N$

Work Step by Step

$U = 4y^3~J$ We can find an expression for $F_y$: $F_y = -\frac{dU}{dy}$ $F_y = -12y^2~N$ We can find $F_y$ at $y = 0$: $F_y = -12y^2~N$ $F_y = -(12)(0)^2~N$ $F_y = 0$ We can find $F_y$ at $y = 1$: $F_y = -12y^2~N$ $F_y = -(12)(1)^2~N$ $F_y = -12~N$ We can find $F_y$ at $y = 2$: $F_y = -12y^2~N$ $F_y = -(12)(2)^2~N$ $F_y = -48~N$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.