#### Answer

The work done by $T_1$ is 1690 J
The work done by $T_2$ is 1065 J
The work done by $T_3$ is -1950 J

#### Work Step by Step

We can find the work done by $T_1$.
$W = T_1\cdot d$
$W = T_1 ~d~cos(\theta)$
$W = (600~N)(3.0~m)~cos(20^{\circ})$
$W = 1690~J$
The work done by $T_1$ is 1690 J.
We can find the work done by $T_2$.
$W = T_2\cdot d$
$W = T_2 ~d~cos(\theta)$
$W = (410~N)(3.0~m)~cos(30^{\circ})$
$W = 1065~J$
The work done by $T_2$ is 1065 J.
We can find the work done by $T_3$.
$W = T_3\cdot d$
$W = T_3 ~d~cos(\theta)$
$W = (650~N)(3.0~m)~cos(180^{\circ})$
$W = -1950~J$
The work done by $T_3$ is -1950 J.