## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

The work done on the particle is equal to the area under the force versus position graph. We can find the work done during the interval 0 - 1 m: $W = F~d$ $W = (4~N)(1~m)$ $W = 4~J$ We can find the work done during the interval 1 - 2 m: $W = F~d$ $W = (4~N)(0.5~m)+(-4~N)(0.5~m)$ $W = 0$ We can find the work done during the interval 2 - 3 m: $W = \frac{1}{2}(-4~N)(1~m)$ $W = -2~J$