Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 8 - Rotational Kinematics - Focus On Concepts - Page 211: 7

Answer

At $t=14s$, the angular velocity of the object is $32rad/s$

Work Step by Step

We have $\omega_0=0rad/s$. After $t=7s$, $\omega=16rad/s$ The angular acceleration of the object is $$\alpha=\frac{\omega-\omega_0}{t}=\frac{16}{7}rad/s^2$$ Next, we still set $\omega_0=0rad/s$. After $t=14s$, the angular velocity of the object is $$\omega=\omega_0+\alpha t=\frac{16}{7}\times14=32rad/s$$
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