## Physics (10th Edition)

Published by Wiley

# Chapter 8 - Rotational Kinematics - Focus On Concepts - Page 211: 3

#### Answer

$t=38.1s$

#### Work Step by Step

The second hand subtends an angle of $2\pi rad$ in $60s$. Its angular speed is $$\omega=\frac{2\pi}{60}=0.105rad/s$$ We have $r=6cm$. In a time t, the second hand moves through an arc $s=24cm$, which corresponds to $$\theta=\frac{s}{r}=4rad$$ The time t it takes is $$t=\frac{\theta}{\omega}=38.1s$$

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