Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 8 - Rotational Kinematics - Focus On Concepts - Page 211: 13


d) is correct.

Work Step by Step

Because angular speed $\omega$ is constant, angular acceleration $\alpha=0rad/s^2$ We have $a_T=r\alpha $. Because $\alpha=0$, $a_T=0rad/s^2$ We have $a_c=r\omega^2$. Because $\omega\ne0$ and $r\ne0$, it follows that $a_c\ne0$ d) is correct.
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