Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 8 - Rotational Kinematics - Focus On Concepts - Page 211: 10


b) is correct.

Work Step by Step

We have $$\omega=\frac{v_T}{r}$$ The first child, whose distance from the axis is $r_1=1.4m$, has $v_{T1}=2.2m/s$. The second child is located $r_2=2.1m$ from the axis. Because $\omega$ is constant, we have $$\frac{v_{T1}}{r_1}=\frac{v_{T2}}{r_2}$$ $$v_{T2}=\frac{v_{T1}\times r_2}{r_1}=3.3m/s$$
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