## Physics (10th Edition)

a) Bow 1 requires more work. b) The additional work is estimated to be $24J$.
a) The force-displacement graph is given, and the value of work equals the area under the line. We can see from the graph that the area under line 1 is greater than the area under line 2, so bow 1 requires more work. b) The additional work corresponds to the number of squares the area of bow 1 has more than the area of bow 2 in graph, which is estimated to be $12$ squares. Each square has an area of $40N\times0.05m=2J$ So the additional work is $2\times12=24J$