Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 6 - Work and Energy - Problems - Page 170: 78

Answer

$W_{wave}=1043J$

Work Step by Step

According to the work-energy theorem, $$W_{nc}=E_f-E_0$$ $$W_{nc}=(\frac{1}{2}mv_f^2+mgh_f)-(\frac{1}{2}mv_0^2+mgh_0)$$ $$W_{nc}=\frac{1}{2}m(v_f^2-v_0^2)+mg(h_f-h_0)$$ We know $v_0=1.4m/s$, $v_f=9.5m/s$, $h_f-h_0=-2.7m$ and $m=59kg$. Therefore, $$W_{wave}=1043J$$
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