Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 6 - Work and Energy - Problems: 77

Answer

a) At h = 20m, KE = 0 J GPE = 392 J Total E = 392 J b) At h = 10m, KE = 196 J GPE = 196 J Total E = 392 J c) At h = 0m, KE = 392 J GPE = 0 J Total E = 392 J

Work Step by Step

a) At h = 20m GPE = mg$\Delta$h = 2(9.8)(20) = 392 J KE = 0 J Total E = 392 J b) At h = 10m, GPE = mg$\Delta$h = 2(9.8)(10) = 196 J Total E = 392 J KE = Total E - GPE = 392 - 196 = 196 J c) At h = 0m, GPE = 0 J Total E = 392 J KE = 392 J
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.