## Physics (10th Edition)

A person's weight on earth is $$W_E=G\frac{mM_E}{r^2}$$ In another planet, whose mass is $2M_E$ and radius $3r$, the person's weight will be $$W_P=G\frac{m(2M_E)}{9r^2}=\frac{2}{9}G\frac{mM_E}{r^2}=0.222W_E$$ (e) is the correct answer.