Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 4 - Forces and Newton's Laws of Motion - Focus On Concepts - Page 112: 9


(e) is the correct answer.

Work Step by Step

A person's weight on earth is $$W_E=G\frac{mM_E}{r^2}$$ In another planet, whose mass is $2M_E$ and radius $3r$, the person's weight will be $$W_P=G\frac{m(2M_E)}{9r^2}=\frac{2}{9}G\frac{mM_E}{r^2}=0.222W_E$$ (e) is the correct answer.
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