## Physics (10th Edition)

Published by Wiley

# Chapter 4 - Forces and Newton's Laws of Motion - Focus On Concepts - Page 112: 18

#### Answer

(e) is the correct answer.

#### Work Step by Step

Since the block is suspended and has no acceleration, if the block has mass $m$ and the tension force in the rope is $T$, we have $$\sum T=mg$$ The tension force $T$ is unchanged in a specific rope, but the way the rope is arranged can affect the number of $T$ forces affecting the block. In A, there is only 1 section of rope holding the block, so $\sum T=T_A$. Therefore, $T_A=mg$ In B, the rope is divided among 3 pulleys, which separate the rope into 3 parts all helping to keep the block in place. Each section of the rope has tension $T$, so $\sum T=3T_B$. Therefore, $T_B=\frac{mg}{3}$ In C, the rope is divided among 2 pulleys, which separate the rope into 2 parts. Each part has tension $T$, so $\sum T=2T_C$. Therefore, $T_C=\frac{mg}{2}$ In conclusion, the tension in ascending order is: B, C, A.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.