# Chapter 3 - Kinematics in Two Dimensions - Problems: 8

$27^{\circ}$

#### Work Step by Step

Length of escalator = $\sqrt (16^{2}-9^{2})$ = $5\sqrt 7$ $sin(\theta) = \frac{6}{5\sqrt 7}$ $\theta$ = $sin^{-1}(\frac{6}{5\sqrt 7}) \approx 27^{\circ}$

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