Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 3 - Kinematics in Two Dimensions - Problems - Page 73: 8



Work Step by Step

Length of escalator = $\sqrt (16^{2}-9^{2})$ = $5\sqrt 7$ $sin(\theta) = \frac{6}{5\sqrt 7}$ $\theta$ = $sin^{-1}(\frac{6}{5\sqrt 7}) \approx 27^{\circ}$
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