## Physics (10th Edition)

Published by Wiley

# Chapter 3 - Kinematics in Two Dimensions - Problems - Page 73: 3

#### Answer

Horizontal component of velocity = 11 m/s Vertical component of velocity = 13 m/s

#### Work Step by Step

v = u + at = 0 + (340)(0.050) = 17 m/s Vertical component of launch velocity = 17 $\times$ sin(51$^{\circ}$) = 13 m/s Horizontal component of launch velocity = 17 $\times$ cos(51$^{\circ}$) = 11 m/s

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