Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 3 - Kinematics in Two Dimensions - Problems - Page 73: 3

Answer

Horizontal component of velocity = 11 m/s Vertical component of velocity = 13 m/s

Work Step by Step

v = u + at = 0 + (340)(0.050) = 17 m/s Vertical component of launch velocity = 17 $\times$ sin(51$^{\circ}$) = 13 m/s Horizontal component of launch velocity = 17 $\times$ cos(51$^{\circ}$) = 11 m/s
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.