Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 3 - Kinematics in Two Dimensions - Problems: 3

Answer

Horizontal component of velocity = 11 m/s Vertical component of velocity = 13 m/s

Work Step by Step

v = u + at = 0 + (340)(0.050) = 17 m/s Vertical component of launch velocity = 17 $\times$ sin(51$^{\circ}$) = 13 m/s Horizontal component of launch velocity = 17 $\times$ cos(51$^{\circ}$) = 11 m/s
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