Answer
47.9 m
Work Step by Step
Let's apply equation 3.5b $S=ut +\frac{1}{2}at^{2}$ to find the traveled time of the bullet.
$\downarrow S=ut +\frac{1}{2}at^{2}$ ; Let's plug known values into this equation.
$0.025\space m=\frac{1}{2}\times 9.8\space m/s^{2}\times t^{2}$
$t^{2}=5.1\times10^{-3}$
$t=0.07\space s$
Let's apply equation 3.5a $S=ut +\frac{1}{2}at^{2}$ to find the displacement between the end of the rifle and the bull's eye.
$\rightarrow S=ut +\frac{1}{2}at^{2}$ ; Let's plug known values into this equation.
$x=670\space m/s\times0.07\space s$
$x=47.9\space m$
The displacement between the end of the rifle and the bull's eye = 47.9 m
