Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems - Page 52: 81

Answer

$$7.2 \times 10^{3} m$$

Work Step by Step

The time required for the woman to reach the water is: Elapsed time$=\frac{d_{\text {woman}}}{v_{\text {woman}}}$ $==>$ Elapsed time $=\left(\frac{4.0 \mathrm{km}}{2.5 \mathrm{m} / \mathrm{s}}\right)\left(\frac{1000 \mathrm{m}}{1.0 \mathrm{km}}\right)$ $=>$ Elapsed time $=1600 \mathrm{s}$ In 1600 s, the dog travels a total distance of $d_{d o g}=v_{d o g} t$ $=>(4.5 m / s)(1600 s)=d_{d o g}$ $=>7.2 \times 10^{3} \mathrm{m}=d_{\mathrm{dog}}$
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