Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems - Page 52: 77

Answer

$$2.273 \mathrm{min}$$

Work Step by Step

Since the electron moves with an average speed, the time is: $$ \frac{x}{v_{a x y}}=t $$ Plugging in known values: $$ \begin{aligned} \frac{x}{v_{\text {avg.}}}=t & \\ &=\frac{(1.5 \mathrm{m})}{\left(1.1 \times 10^{-2} \mathrm{m} \cdot \mathrm{s}^{-1}\right)} \\ &=136.36 \mathrm{s} \end{aligned} $$ Converting to minutes: $$ 2.273 \mathrm{min}=136.36 \mathrm{s} \times \frac{(\mathrm{min})}{(60 \mathrm{s})}=t $$ $$ \begin{array}{l} 2.273 \mathrm{min}=t \\ \end{array} $$
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