Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 14 - The Ideal Gas Law and Kinetic Theory - Problems - Page 385: 37

Answer

(a) $46.3\space m^{2}/s^{2}$ (b) $40.1\space m^{2}/s^{2}$

Work Step by Step

(a) We can write, $$\bar{v^{2}}=\frac{1}{3}(v_{1}^{2}+v_{2}^{2}+v_{3}^{2})$$ Let's plug known values into this equation. $\bar{v^{2}}=\frac{1}{3}[(3\space m/s)^{2}+(7\space m/s)^{2}+(9\space m/s)^{2}]=46.3\space m^{2}/s^{2}$ (b) We can write, $$(\bar{v})^{2}=[\frac{1}{3}(v_{1}+v_{2}+v_{3})]^{2}$$ Let's plug known values into this equation. $(\bar{v})^{2}=[\frac{1}{3}(3\space m/s+7\space m/s+9\space m/s)]^{2}=40.1\space m^{2}/s^{2}$
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