Answer
1.02
Work Step by Step
Here we use Boyle's law $P_{1}V_{1}=P_{2}V_{2}$ to find the ratio of volumes.
$P_{1}V_{1}=P_{2}V_{2}=>\frac{V_{1}}{V_{2}}=\frac{P_{2}}{P_{1}}$
$\frac{V_{1}}{V_{2}}=\frac{P_{1}+\rho gh}{P_{1}}=1+\frac{\rho gh}{P_{1}}$ ; Let's plug known values into this equation.
$\frac{V_{1}}{V_{2}}=1+\frac{(1000\space kg/m^{3})(9.8\space m/s^{2})(0.2\space m)}{1.01\times10^{5}Pa}=1.02$
