Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 10 - Simple Harmonic Motion and Elasticity - Problems - Page 276: 27


a) $k=58.8N/m$ b) $\omega=11.43rad/s$

Work Step by Step

a) The energy is conserved, so $$E_0=E_f$$ In this exercise, we only need to look at elastic energy and gravitational energy. Since the block drops $0.15m$, its height changes from $h_0=0.15m$ to $h_f=0m$. In reverse, the spring's position changes from $x_0=0m$ to $x_f=0.15m$ $$mgh_0=\frac{1}{2}kx_f^2$$ $$k=\frac{2mgh_0}{x_f^2}$$ The block's mass $m=0.45kg$, so $$k=58.8N/m$$ b) The angular frequency is $$\omega=\sqrt{\frac{k}{m}}=11.43rad/s$$
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