Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 10 - Simple Harmonic Motion and Elasticity - Problems - Page 276: 25



Work Step by Step

The work needed to be done to ready the pen for writing is $$W=\frac{1}{2}kx_0^2-\frac{1}{2}kx_f^2$$ The spring constant $k=250N/m$, the spring's initial point $x_0=5mm=5\times10^{-3}m$ and final point $x_f=5+6=11mm=1.1\times10^{-2}m$. Therefore, $$W=-0.012J$$
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