Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 10 - Simple Harmonic Motion and Elasticity - Problems - Page 276: 26


a) $W=-184J$ b) $W=184J$ c) $W=0J$

Work Step by Step

The total work done by the restoring force is $$\sum W=\frac{1}{2}k(x_0^2-x_f^2)$$ In this exercise, $k=46N/m$ a) $x_0=1m$ and $x_f=3m$ $$\sum W=\frac{1}{2}\times46\Big(1^2-3^2\Big)=-184J$$ b) $x_0=-3m$ and $x_f=1m$ $$\sum W=\frac{1}{2}\times46\Big((-3)^2-1^2\Big)=184J$$ c) $x_0=-3m$ and $x_f=3m$ $$\sum W=\frac{1}{2}\times46\Big((-3)^2-3^2\Big)=0J$$
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