## Physics (10th Edition)

a) $W=-184J$ b) $W=184J$ c) $W=0J$
The total work done by the restoring force is $$\sum W=\frac{1}{2}k(x_0^2-x_f^2)$$ In this exercise, $k=46N/m$ a) $x_0=1m$ and $x_f=3m$ $$\sum W=\frac{1}{2}\times46\Big(1^2-3^2\Big)=-184J$$ b) $x_0=-3m$ and $x_f=1m$ $$\sum W=\frac{1}{2}\times46\Big((-3)^2-1^2\Big)=184J$$ c) $x_0=-3m$ and $x_f=3m$ $$\sum W=\frac{1}{2}\times46\Big((-3)^2-3^2\Big)=0J$$