Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 9 - Center of Mass and Linear Momentum - Problems - Page 249: 31b

Answer

The magnitude of the average force on the passenger during the collision is $~~4.78\times 10^5~N$

Work Step by Step

In part (a), we found that the magnitude of the impulse is $~~2390~kg~m/s$ We can find the magnitude of the average force on the passenger during the collision: $F~t = J$ $F = \frac{J}{t}$ $F = \frac{2390~kg~m/s}{5.0\times 10^{-3}~s}$ $F = 4.78\times 10^5~N$ The magnitude of the average force on the passenger during the collision is $~~4.78\times 10^5~N$.
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