Answer
$1.82\ kN$
Work Step by Step
Initial speed of the hand $v_i = 13\ m/s$
Final speed of the hand $v_f = 0\ m/s$
Mass of the hand $m=0.7\ kg$
Magnitude of impulse is $J=9.1\ kg.m/s$
Using the relation between force and impulse to find the average Force:
$F_{avg} =\frac{J}{\Delta t}$
$F_{avg} =\frac{9.1\ kg.m/s}{5\times 10^{-3}\ s}$
$F_{avg} = 1820\ kgm/s^2 = 1.82\ kN$
