Answer
$217\ N.s$
Work Step by Step
Given:
mass $m=70\ kg$
height $h=0.50\ m$
From kinematic equation $v^2-u^2 = 2as$;
$v^2-0 = 2gh$
$v=\sqrt{2gh}$
$v=\sqrt {2\times 9.8\ m/s^2\times0.50\ m}$
$v=3.10\ m/s$
Magnitude of impulse $J=\Delta P$. Therefore;
$J=m(v-u)$
$J=m(v-0)$
$J=(70\ kg)(3.1\ m/s)$
$J=217\ N.s$
