Answer
The magnitude of the impulse during each impact is $~~1.0~kg~m/s$
Work Step by Step
The impulse is equal to the area under the force versus time graph.
We can find the magnitude of the impulse during each impact:
$J = \frac{1}{2}F_{max}~t$
$J = \frac{1}{2}(200~N)(10\times 10^{-3}~s)$
$J = 1.0~kg~m/s$
The magnitude of the impulse during each impact is $~~1.0~kg~m/s$
