Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 206: 43a

Answer

Work Done $= 5.6$ $J$

Work Step by Step

$Work = F\times d$ Work done by collie's force = Force applied by collie $\times$ displacement of box $= 8N\times 0.70 m$ $= 5.6$ $Joules$
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